14a^2+11a+2=0

Solution for 14a^2+11a+2=0 equation:

14a^2+11a+2=0

a = 14; b = 11; c = +2;
Δ = b2-4ac
Δ = 112-4·14·2
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-3}{2*14}=\frac{-14}{28}
=-1/2
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+3}{2*14}=\frac{-8}{28}
=-2/7
$